SOLUTION: 8d fewer than 6 out of the next 20 business days. If this actually happened, might it shake you confidence in the statement p = 0.60? Might it make you suspect that p is less than

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: 8d fewer than 6 out of the next 20 business days. If this actually happened, might it shake you confidence in the statement p = 0.60? Might it make you suspect that p is less than       Log On


   

Question 142922: 8d fewer than 6 out of the next 20 business days. If this actually happened, might it shake you confidence in the statement p = 0.60? Might it make you suspect that p is less than 0.60? Explain.
8e more than 17 of the next 20 business days. If this actually happened, might you suspect that p is greater than 0.60? Explain.

This problem has me so stumped if you could help I would be very greatful
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Find the vertex, symmetry and the maximum or minimum value of f(x)
Graph the function
F(x)=1/3(x+3)^2+2
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Rewrite as:
y-2 = (1/3)(x+3)^2
Vertex is at (-3,2)
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Axis of symmetry is x = -3
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Since 1/3 is greater than zero, the parabola opens up.
Therefore (-3,2) is the lowest point on he curve
So the miniumum value for y is 2
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Graph:
graph%28400%2C300%2C-10%2C10%2C-10%2C10%2C%281%2F3%29%28x%2B3%29%5E2%2B2%29
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Cheers,
Stan H.