SOLUTION: Solving 6x^2+3x-18=0,using quadratic formula. would that be ax^+bx+c=0.

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Question 140923: Solving 6x^2+3x-18=0,using quadratic formula. would that be ax^+bx+c=0.
Found 2 solutions by checkley77, stanbon:
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
6x^2+3x-18=0
Following is the quadratic formula:
x=%28-b%2B-sqrt%28b%5E2-4%2Aa%2Ac%29%29%2F%282%2Aa%29
x=(-3+-sqrt[3^2-4*6*-18])/2*6
x=(9+-sqrt[9+432])/12
x=(9+-sqrt441)/12
x=(9+-21)/12
x=(3+21)/12
x=24/12
x=2 answer.
x=(3-21)/12
x=-18/12
x=-1.5 answer.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
6x^2+3x-18=0,using quadratic formula
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Formula:
x = [-b +- sqrt(b^2-4ac)]/(2a)
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Your problem:
x = [-3 +- sqrt(9-4*6*-18)]/12
x = [-3 +- sqrt(441)]/12
x = [-3 +- 21]/12
x = (-3+21)/12 or x = (-3-21)/12
x =(3/2) or x = -2
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Cheers,
Stan H.