SOLUTION: Help me translate this into a quadratic equation and solve. Thanks! Three consecutive even integers are such that the square of the third is 76 more than the square of the secon

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Question 139337: Help me translate this into a quadratic equation and solve. Thanks!
Three consecutive even integers are such that the square of the third is 76 more than the square of the second. Find the three integers.
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
LET X, X+2, & X+4 BE THE 3 CONSECUTIVE EVEN INTEGERS.
(X+4)^2=(X+2)^2+76
X^2+8X+16=X^2+4X+4+76
8X-4X=4+76-16=0
4X=64
X=64/4
X=16 ANSWER.
16+2=18 FOR THE MIDDLE NUMBER.
16+4=20 FOR THE THIRD NUMBER.
PROOF:
20^2=18^2+76
400=324+76
400=400