SOLUTION: The perimeter of a rectangle is 108 inches. The length exceeds the width by 8 inches. Find the length and the width. Again please help me.

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: The perimeter of a rectangle is 108 inches. The length exceeds the width by 8 inches. Find the length and the width. Again please help me.      Log On


   

Question 137504: The perimeter of a rectangle is 108 inches. The length exceeds the width by 8 inches. Find the length and the width.
Again please help me.
Answer by oscargut(2103) About Me  (Show Source):
You can put this solution on YOUR website!
Let L=length and W=width
then Perimeter=P=2(L+W)=108
L=W+8
so
2(2W+8)=108
4W=96
W=24
L=32