SOLUTION: The function f(x) = 0.0037x2 – 0.46x +36.63 models the average age at which Kentucky men were first married x years after 1900. In which year was this average age at a minimum?
Question 136231: The function f(x) = 0.0037x2 – 0.46x +36.63 models the average age at which Kentucky men were first married x years after 1900. In which year was this average age at a minimum? What was the average age at first marriage for that year?
Please help me. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! The function f(x) = 0.0037x^2 – 0.46x +36.63 models the average age at which Kentucky men were first married x years after 1900. In which year was this average age at a minimum? What was the average age at first marriage for that year?
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Minimum occurs when x=-b/2a = -(-0.46)/(2(0.0037)) = 62.16
f(62.16216...) = 22.333
Average age was 22 1/3 yrs.
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Cheers,
Stan H.