Question 134016: use the square root method to find solutions for the equation
(3x-2)^2=-9 Found 3 solutions by checkley71, snwbrdfrk, Earlsdon:Answer by checkley71(8403) (Show Source):
You can put this solution on YOUR website! i dont know if you have worked with imaginary numbers or not so if this isnt what your looking for than im sorry
but to solve the equation (3x-2)^2=-9 the first thing you need to do is put the square root over the numbers so it would be
square root of(3x-2)^2= square root of -9
the square root of (3x-2)^2 cancels out because there is a square root and a power of 2. the equation should now look like this
3x-2=square root of -9
this is where the imaginary number comes in
since you cant take the square root of a negative number you have to replace the number with an i.
so the square root of -9 would now be 3i.
now the equation looks like this.
3x-2=3i
now to get the x by itself you now need to add 2 to both sides.
3x-2+2=3i+2
3x=3i+2
now we need to make the 3 go to the other side and since it is connected to the x we need to divide instead of add or subtract.
3x/3=(3i+2)/3
the three cancels
x=(3i+2)/3
im not totally positive if the 3 cancels out on the (3i+2)/3 part because its on an imaginary number but i think it does. im not going to do it because its not wrong the way i have it, but it might be able to be reduced. so ask your teacher if you want to. im sorry though.
You can put this solution on YOUR website! Solve for x: Take the square root of both sides. or Add 2 to both sides. Divide both sides by 3. which can be written as:
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