SOLUTION: 4 over x = 3 over x squared + 5 LCD= x^2 a=5 b=-4 c=3 0=5x^2-4x+5 Total answer i got= 4 plus minus square root -44 over 10 is this right???? are they both no solution?

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: 4 over x = 3 over x squared + 5 LCD= x^2 a=5 b=-4 c=3 0=5x^2-4x+5 Total answer i got= 4 plus minus square root -44 over 10 is this right???? are they both no solution?      Log On


   

Question 133900: 4 over x = 3 over x squared + 5
LCD= x^2
a=5 b=-4 c=3
0=5x^2-4x+5
Total answer i got= 4 plus minus square root -44 over 10
is this right???? are they both no solution?
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
4/x=(3/x^2) +5 I assume that this is the problem.
4x=3+5x^2
5x^2-4x+3=0
x=2/5 + sqrt(11)/5 * i, x=2/5 - sqrt(11)/5 * i
.
Ed
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Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 5x%5E2%2B-4x%2B3+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%28-4%29%5E2-4%2A5%2A3=-44.

The discriminant -44 is less than zero. That means that there are no solutions among real numbers.

If you are a student of advanced school algebra and are aware about imaginary numbers, read on.


In the field of imaginary numbers, the square root of -44 is + or - sqrt%28+44%29+=+6.6332495807108.

The solution is , or
Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+5%2Ax%5E2%2B-4%2Ax%2B3+%29