Question 131997: Find the standard form of the equation for the parabola having a vertex (-3,6) that contains the origin
Found 2 solutions by rapaljer, stanbon:
Answer by rapaljer(4671)   (Show Source):
You can put this solution on YOUR website! The first step is to find the slope between (-3,6) and (0,0)!
The equation is y=-2x+0
This can be written in standard form by adding +2x to each side:
2x+y=0
R^2
Answer by stanbon(75887)  (Show Source):
You can put this solution on YOUR website! Find the standard form of the equation for the parabola having a vertex (-3,6) that contains the origin.
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Form: y = ax^2+bx+c
Using (0,0) you find 0 = a*0+b*0+c
So c = 0
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Foem y = ax^2+bx
Using (-3,6) you find 6 = a(-3)^2+b(-3)
6 = 9a -3b
2 = 3a-b
b = 3a-2
Let a=1, then b = 3*1-2 = 1
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So a=1,b=1,c=0
EQUATION:
y = x^2+x
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Cheers,
Stan H.
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