SOLUTION: IN MY ALGEBRA 2 BOOK ON PAGE 296 I'M HAVING A HARD TIME UNDERSTANDING HOW I FIND THE SOLUTION. THE SOLUTION FUNCITON IS, X=-b+ - SQUARE UNDER b SQ. 2 -4ac/2a.okay now how do I fiqu

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: IN MY ALGEBRA 2 BOOK ON PAGE 296 I'M HAVING A HARD TIME UNDERSTANDING HOW I FIND THE SOLUTION. THE SOLUTION FUNCITON IS, X=-b+ - SQUARE UNDER b SQ. 2 -4ac/2a.okay now how do I fiqu      Log On


   

Question 130636This question is from textbook ALGEBRA 2
: IN MY ALGEBRA 2 BOOK ON PAGE 296 I'M HAVING A HARD TIME UNDERSTANDING HOW I FIND THE SOLUTION. THE SOLUTION FUNCITON IS, X=-b+ - SQUARE UNDER b SQ. 2 -4ac/2a.okay now how do I fiqure out the solution? I'm stuck at this p.for ex.x sq.2 minus 4x + 10=0,using the discriminant function i've got ( -4)sq.2 -4(1)(10)=24.i know how to set the solution function up (X=-b+ - SQUARE UNDER b SQ. 2 -4ac/2a) x=-4+ - sq.root4 sq.2 minus 4(1)(10). now where do i go from there.i don't understand how to first solve it. do i use a calculator for that part or not?
well I reallywould appreciate if you can help me out with my problem , it would mean alot to me, since my test on this is on friday, at my school!
thanks! This question is from textbook ALGEBRA 2

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for x%5E2-4x%2B10+=+0 x using the quadratic formula: x+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F2a Make the appropriate substitutions of a = 1, b = -4, and c = 10.
x+=+%28-%28-4%29%2B-sqrt%28%28-4%29%5E2-4%281%29%2810%29%29%29%2F2%281%29
x+=+%284%2B-sqrt%2816-40%29%29%2F2
x+=+%284%2B-sqrt%28-24%29%29%2F2
x+=+%284%2B-sqrt%28-4%2A6%29%29%2F2
x+=+4%2F2%2B2%2Asqrt%28-6%29%2F2 or x+=+4%2F2+-+2%2Asqrt%28-6%29%2F2 Simplify.
x+=+2%2Bsqrt%286%29i or x+=+2-sqrt%286%29i