SOLUTION: The length of a rectangle is 50ft. The perimeter of the rectangle is 275ft more than the width of the rectangle. Find the width. Here's what I have 2(50)+2w = 275-w 100+2w = 2

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: The length of a rectangle is 50ft. The perimeter of the rectangle is 275ft more than the width of the rectangle. Find the width. Here's what I have 2(50)+2w = 275-w 100+2w = 2      Log On


   

Question 127313: The length of a rectangle is 50ft. The perimeter of the rectangle is 275ft more than the width of the rectangle. Find the width.
Here's what I have
2(50)+2w = 275-w
100+2w = 275-w
+w +w
100+3w = 275
-100 -100
3w - 175
3w/3 175/3
w=58.3333...
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
Looks like the correct answer to me. :)