SOLUTION: Daniel and Jonathan drove separately to a park that is 12 kilometers away. Daniel left at 9:41 a.m. and arrived at 10:29 a.m. Jonathan left at 10:35 a.m. and arrived at 10:50 a.m.
Question 126899: Daniel and Jonathan drove separately to a park that is 12 kilometers away. Daniel left at 9:41 a.m. and arrived at 10:29 a.m. Jonathan left at 10:35 a.m. and arrived at 10:50 a.m. Jonathan drove his car at a rate that averaged 33 kph faster than Daniel. What were Daniel's and Jonathan's speeds? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Daniel and Jonathan drove separately to a park that is 12 kilometers away. Daniel left at 9:41 a.m. and arrived at 10:29 a.m. Jonathan left at 10:35 a.m. and arrived at 10:50 a.m. Jonathan drove his car at a rate that averaged 33 kph faster than Daniel. What were Daniel's and Jonathan's speeds?
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Find D's travel time: 9:41 to 10:29 = 48 min = 48/60 = .8 hr
Find J's travel time: 10:35 to 10:50 = 15 min = 15/60 = .25 hr
:
Let s = D's rate of speed
Then
(s+33) = J's rate of speed
:
They both traveled the same distance;Write a distance equation Dist = time * speed
:
D's dist = J's dist
.8s = .25(s+33)
:
.8s = .25s + 8.25
:
.8s - .25s = 8.25
:
.55s = 8.25
s =
s = 15 km/hr is D's speed
then
15 + 33 = 48 km/hr is J's speed
:
:
Check solutions by finding the distances (they should be the same)
.8 * 15 = 12 km
.25 * 48 = 12
