SOLUTION: How do i solve (3x-5)squard=12 by using the root propert?

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Question 125483: How do i solve (3x-5)squard=12 by using the root propert?
Found 2 solutions by josmiceli, MathLover1:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
%283x+-+5%29%5E2+=+12
Take the square root of both sides
There are 2 square roots, + and -
%283x+-+5%29+=+sqrt%2812%29
3x+-+5+=+2%2Asqrt%283%29
x+=+%282%2Asqrt%283%29+%2B+5%29+%2F+3 answer
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-%283x+-+5%29+=+sqrt%2812%29
-3x+%2B+5+=+2%2Asqrt%283%29
x+=+%285+-+2%2Asqrt%283%29%29+%2F+3 answer
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check the answers
%283x+-+5%29%5E2+=+12
%283%2A%28%282%2Asqrt%283%29+%2B+5%29+%2F+3%29+-+5%29%5E2+=+12
%282%2Asqrt%283%29+%2B+5+-+5%29%5E2+=+12
%282%2Asqrt%283%29%29%5E2+=+12
4%2A3+=+12
12+=+12
OK
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%283x+-+5%29%5E2+=+12
%283%2A%28%285+-+2%2Asqrt%283%29%29+%2F+3%29+-+5%29%5E2+=+12
%285+-+2%2Asqrt%283%29+-+5%29%5E2+=+12
%28-2%2Asqrt%283%29%29%5E2+=+12
4%2A3+=+12
12+=+12
OK

Answer by MathLover1(20849) About Me  (Show Source):