SOLUTION: how do you express f(x)=-3(x-2)^2+5 in standard form? What formula do you use?

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Question 123857: how do you express f(x)=-3(x-2)^2+5 in standard form? What formula do you use?
Found 3 solutions by stanbon, johnnico6426, solver91311:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
express f(x)=-3(x-2)^2+5 in standard form
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f(x) = 3(x^2-4x+2)+5
f(x) = 3x^2-12x+11
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Cheers,
Stan H.

Answer by johnnico6426(16) About Me  (Show Source):
You can put this solution on YOUR website!
To put a quadratic equation in standard form, it must follow the format:
y=ax%5E2%2Bbx%2Bc
To put the given into standard form, we must distribute 3 with %28x-2%29%28x-2%29. (%28x-2%29%28x-2%29=%28x-2%29%5E2.) If you do it, you should come up with -3x%5E2%2B12x-12. The only thing left to do is to add 5 to 12 in order to simplify it. In conclusion, the equation f%28x%29=-3%28x-2%29%5E2%2B5 in standard form is y=3x%5E2%2B12x-17.

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!
Standard form is f%28x%29=ax%5E2%2Bbx%2Bc, so expand the binomial using FOIL and collect terms.