SOLUTION: A rectangular field had a length of x^3 + 2x^2 – 4 feet and a width of 4x^2 – 5 feet. Express the area as a polynomial in x.

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: A rectangular field had a length of x^3 + 2x^2 – 4 feet and a width of 4x^2 – 5 feet. Express the area as a polynomial in x.       Log On


   

Question 123291: A rectangular field had a length of x^3 + 2x^2 – 4 feet and a width
of 4x^2 – 5 feet. Express the area as a polynomial in x.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
A rectangular field had a length of x^3 + 2x^2 – 4 feet and a width
of 4x^2 – 5 feet. Express the area as a polynomial in x.
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Area = length*width
Area = (x^3+2x^2-4)*(4x^2-5)
=4x^5+8x^4-16x^2-5x^3-10x^2+20
=4x^5+8x^4-5x^3-26x^2+20
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Cheers,
Stan H.