SOLUTION: how to calculate the vertex of y=x^2-2x-3

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Question 123243This question is from textbook Algebra 2
: how to calculate the vertex of y=x^2-2x-3 This question is from textbook Algebra 2

Answer by solver91311(24713) About Me  (Show Source):
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Discussion







The vertex of any parabola in the form y=f%28x%29=ax%5E2%2Bbx%2Bc is at the point

(-b%2F2a,f%28-b%2F2a%29) 










Solution







For y=f%28x%29=x%5E2-2x-3



a=1

b=-2





-b%2F2a=%28-%28-2%29%29%2F%282%2A1%29=2%2F2=1

f%281%29=%281%29%5E2-2%281%29-3=1-2-3=-4





The vertex is at (1,-4)










Check Answer







graph%28600%2C600%2C-5%2C5%2C-5%2C5%2Cx%5E2-2x-3%29