SOLUTION: If t is a real number, what is the maximum possible value of the expression -t^2 + 8t -4 - 5t^2 + 14t + 55?

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Question 1209303: If t is a real number, what is the maximum possible value of the expression -t^2 + 8t -4 - 5t^2 + 14t + 55?
Found 6 solutions by josgarithmetic, math_tutor2020, mccravyedwin, Edwin McCravy, AnlytcPhil, timofer:
Answer by josgarithmetic(39617) About Me  (Show Source):
Answer by math_tutor2020(3817) About Me  (Show Source):
You can put this solution on YOUR website!

I'll use x in place of t.
-x%5E2+%2B+8x+-4+-+5x%5E2+%2B+14x+%2B+55
Combine like terms to get
-6x%5E2+%2B+22x+%2B+51

We could follow the process of completing the square, but I'll use a shortcut.
The vertex of y+=+ax%5E2%2Bbx%2Bc is at (h,k) where h+=+-b%2F%282a%29

Compare -6x%5E2+%2B+22x+%2B+51 with ax%5E2%2Bbx%2Bc to see that a = -6, b = 22, c = 51

So,
h+=+-b%2F%282a%29
h+=+-22%2F%282%2A%28-6%29%29
h+=+11%2F6
This is the x coordinate of the vertex.

Plug it into the previous expression to find that
-6x%5E2+%2B+22x+%2B+51
= -6%2811%2F6%29%5E2+%2B+22%2811%2F6%29+%2B+51
= 427%2F6
This is the y coordinate of the vertex and it's largest output possible for -6x%5E2+%2B+22x+%2B+51

The vertex is located at (11/6, 427/6) which is the highest point of this parabola.

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Answer: 427/6
This is approximately equal to 71.166667 where the 6's go on forever but we have to round at some point.

Verification using WolframAlpha

Answer by mccravyedwin(407) About Me  (Show Source):
You can put this solution on YOUR website!

Judging by other problems I think you've posted, I think
the way you want it done is by completing the square:

-t%5E2+%2B+8t+-4+-+5t%5E2+%2B+14t+%2B+55

-6t%5E2%2B22t%2B51

Factor -6 out of the first two terms

-6%28t%5E2-expr%2822%2F6%29t%29%2B51

-6%28t%5E2-expr%2811%2F3%29t%29%2B51

Complete the square inside the parentheses:

1. Multiply the coefficient of t by 1/2
    %28-11%2F3%29%281%2F2%29=-11%2F6
2. Square what you got:
    %28-11%2F6%29%5E2=121%2F36
3. Add and subtract that inside the parentheses
 
-6%28t%5E2-expr%2811%2F6%29t%2B121%2F36-121%2F36%29%2B51

Factor the first three terms in the parentheses:

-6%28%28t-11%2F6%29%5E2-expr%28121%2F36%29%5E%22%22%29%2B51

Distribute the -6, leaving the square of a binomial intact:

-6%28t-11%2F6%29%5E2+%2B+121%2F36%2B51

We want to make this as large as possible, so we make the
only non-positive term as small as possible.  Since it's a 
squared term the greatest (smallest amount of subtraction) 
it can be is 0, so the expression will be largest when 
t = 11/6.  Substituting:

-6%280%29%5E2+%2B+121%2F6%2B51

121%2F6+%2B+51

121%2F6+%2B+51%286%2F6%29

121%2F6+%2B+306%2F6

427%2F6   <---answer

Edwin

Answer by Edwin McCravy(20055) About Me  (Show Source):
Answer by AnlytcPhil(1806) About Me  (Show Source):
You can put this solution on YOUR website!
I still had not corrected every step in my solution above, but now it
is completely correct.

Edwin

Answer by timofer(104) About Me  (Show Source):
You can put this solution on YOUR website!
The quadratic expression, simplified is -6t%5E2%2B22t%2B51