SOLUTION: A box has a certain length, width, and height. The length of the box is equal to twice its width, as well as equal to 8 less than its height. If the total surface area of the box
Question 1209114: A box has a certain length, width, and height. The length of the box is equal to twice its width, as well as equal to 8 less than its height. If the total surface area of the box is 480, then what is the height of the box? Answer by math_tutor2020(3816) (Show Source):
"length is twice the width" ---> "width is half the length".
"length is 8 units smaller than the height" ---> "height is 8 units longer compared to length".
x = length
x/2 = 0.5x = width
x+8 = height
S = surface area of the box
S = 2*(length*width + length*height + width*height)
480 = 2*(x*0.5x + x*(x+8) + 0.5x*(x+8))
480 = 2*(0.5x^2 + x^2+8x + 0.5x^2+4x)
480 = 2*(2x^2 +12x)
480 = 4x^2 +24x
4x^2+24x-480 = 0
4(x^2+6x-120) = 0
x^2+6x-120 = 0/4
x^2+6x-120 = 0
Plug a = 1, b = 6, c = -120 into the quadratic formula.
or
or
Ignore the negative x value.
A negative length makes no sense.
Each decimal value mentioned is approximate.
Round it however your teacher instructs.
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