SOLUTION: a baseball team held a fundraising car wash. They charged $4 for each car and $6 for each truck. They washed 50 cars and trucks and collected $210. How many of each type of vehicle
Question 1208864: a baseball team held a fundraising car wash. They charged $4 for each car and $6 for each truck. They washed 50 cars and trucks and collected $210. How many of each type of vehicle did they wash? Found 3 solutions by josgarithmetic, timofer, greenestamps:Answer by josgarithmetic(39617) (Show Source):
Here are a couple of non-algebraic methods for solving the problem.
(1) by logical reasoning and simple arithmetic....
If all 50 vehicles had been cars, the amount they would have collected is 50($4) = $200
but the actual amount was $10 more than that
they collect $2 more for each truck than for each car
the number of trucks they had to wash to make the additional $10 is $10/$2 = 5.
ANSWER: 5 trucks (and 50-5 = 45 cars)
(2) as an unusual type of "mixture" problem....
You are "mixing" cars at $4 each and trucks at $6 each and getting an average of $210/50 = $4.20
Use a number line if it helps to see that $4.20 is 1/10 of the way from $4 to $6.
That means 1/10 of the total 50 vehicles were trucks.
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