SOLUTION: After reducing by an equal amount the length and width of a rectangle which were originally 8cm and 5cm respectively.The area of the new rectangle is 18cm square.Find the dimension

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: After reducing by an equal amount the length and width of a rectangle which were originally 8cm and 5cm respectively.The area of the new rectangle is 18cm square.Find the dimension      Log On


   



Question 1208274: After reducing by an equal amount the length and width of a rectangle which were originally 8cm and 5cm respectively.The area of the new rectangle is 18cm square.Find the dimensions of the rectangle

Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


First get some good mental exercise by solving the problem informally using logical reasoning and simple arithmetic.

The difference between the length and width of the original rectangle is 8-5 = 3cm. The length and width were reduced by the same amount, so the difference between the length and width of the new rectangle is still 3cm. The area of the new rectangle is 18 sq cm, so find two numbers whose difference is 3 and whose product is 18: 6 and 3. So the dimensions of the new rectangle are 6cm and 3cm.

Now solve the problem using formal algebra, which is probably what you are wanting to do.

Let x = # of cm by which the length and width were reduced.

The dimensions of the new rectangle are 8-x and 5-x; the area (length times width) is 18:

%288-x%29%285-x%29=18
40-8x-5x%2Bx%5E2=18
40-13x%2Bx%5E2=18
x%5E2-13x%2B22=0
%28x-11%29%28x-2%29=0

x = 11 or x = 2

Obviously x = 11 makes no sense in the given problem, so x is 2. So the dimensions of the new rectangle are

ANSWERS: 8-2 = 6cm and 5-2 = 3cm