SOLUTION: what is the height of the coin when it is tossed? -16x^2+96x+112

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Question 1208234: what is the height of the coin when it is tossed? -16x^2+96x+112
Found 2 solutions by mananth, ikleyn:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
what is the height of the coin when it is tossed? -16x^2+96x+112
The problem has not been written correctly
h(x) = -16x^2+96x+112
h isheight and x is the time
find the maximum height (whic we need to find the vertex of this quadratic equation.
using the formula for the vertex of a parabola:
x= -b/2a
a=-16 , b=96
x= -96/-32= 3 seconds
maximum height occurs at x =3 seconds
plug x = 3 in the equation
h(3) = -16*3^2+96*3+112 =256

The maximum height of the coin is 256 units

Answer by ikleyn(52778) About Me  (Show Source):
You can put this solution on YOUR website!
.
what is the highlight%28highlight%28maximum%29%29 height of the coin when it is tossed? -16x^2+96x+112
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From the form of this equation, we see that the units of height in this problem are feet.

Therefore, from the solution by @mananth, we can conclude that the maximum height is 256 feet.