SOLUTION: What is the equation of the axis of symmetry for the parabola y=2x^2-6x+5?

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Question 120779: What is the equation of the axis of symmetry for the parabola y=2x^2-6x+5?
Answer by bucky(2189) About Me  (Show Source):
You can put this solution on YOUR website!
If you are familiar with the quadratic formula, then you know that a quadratic equation of
the generic standard form:
.
ax%5E2+%2B+bx+%2B+c+=+0
.
has as its solutions for x the values that are given by:
.
x+=+-b%2F%282%2Aa%29+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%2F%282%2Aa%29+
.
The first term on the right side specifies the axis of symmetry. In other words, the axis
of symmetry is given by:
.
x+=+-b%2F%282%2Aa%29
.
Now in your given equation, set y equal to zero, and you have the standard form:
.
2x%5E2+-+6x+%2B+5+=+0
.
by comparing this equation term by term with the generic form, you can see that a = 2, b = -6,
and c = +5 for this problem. Return to the equation for the axis of symmetry and by substituting
the values for a and b you get:
.
x+=+-b%2F%282%2Aa%29+=+-%28-6%29%2F%282%2A2%29+=+6%2F4+=+3%2F2
.
This tells you that the equation:
.
x+=+3%2F2
.
is the equation of the axis of symmetry. It is a vertical line through the point 3%2F2 on the
x-axis.
.
Hope this helps you to see the way you can find the axis of symmetry of a quadratic
expression.
.