SOLUTION: Find the vertex of y=3x^2+18x+24
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Question 1207030
:
Find the vertex of y=3x^2+18x+24
Found 2 solutions by
josgarithmetic, math_tutor2020
:
Answer by
josgarithmetic(39617)
(
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):
You can
put this solution on YOUR website!
Vertex is read directly from the equation in this form.
(-3,-3)
Answer by
math_tutor2020(3816)
(
Show Source
):
You can
put this solution on YOUR website!
Answer:
(-3, -3)
Explanation
Compare y=3x^2+18x+24 to the template y = ax^2+bx+c
a = 3
b = 18
c = 24
The vertex is located at (h,k)
Let's determine the x coordinate of the vertex.
h = -b/(2a)
h = -18/(2*3)
h = -3
Plug this into the equation to find the y coordinate of the vertex.
y = 3x^2+18x+24
y = 3*(-3)^2+18(-3)+24
y = -3
The vertex is located at (h,k) =
(-3, -3)
We go from vertex form
y = a(x-h)^2 + k
to
y = 3(x-(-3))^2 + (-3)
y = 3(x + 3)^2 - 3