SOLUTION: Solve the system using the substitution method. If there is exactly one solution, write as an ordered pair. If not, choose one of the other options. {(x,-,5y,=,32),(2x,+,4y,=,-3

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Solve the system using the substitution method. If there is exactly one solution, write as an ordered pair. If not, choose one of the other options. {(x,-,5y,=,32),(2x,+,4y,=,-3      Log On


   

Question 1205741: Solve the system using the substitution method. If there is exactly one solution, write as an ordered pair. If not, choose one of the other options.
{(x,-,5y,=,32),(2x,+,4y,=,-34):}
A. One solution:
B. No solution
C. Infinite number of solutions
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

x-5y=32......eq.1
2x%2B4y=-34.....eq.2
---------------------
start with eq.1 and solve for+x
x-5y=32
x=5y%2B32......eq.1

go to eq.2 and substitute x

2%285y%2B32%29%2B4y=-34.....eq.2, solve for y
10y%2B64%2B4y=-34
14y=-34-64
14y=-98
y=-98%2F14
y=-7

go to eq.1, substitute y
x=5%2A%28-7%29%2B32......eq.1
x=-35%2B32
x=-3
answer:
A. One solution:
ordered pair: (-3, -7)