SOLUTION: The sum of two numbers is 32. One number is 10 less than the other. Find the numbers. The smaller number is: The larger number is Ervin has been offered positions by two

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: The sum of two numbers is 32. One number is 10 less than the other. Find the numbers. The smaller number is: The larger number is Ervin has been offered positions by two      Log On


   

Question 1205697: The sum of two numbers is 32. One number is 10 less than the other. Find the numbers.
The smaller number is:
The larger number is

Ervin has been offered positions by two car dealers. The first company pays a salary of $20,000 plus a commission of $300 for each car sold. The second pays a salary of $15,000 plus a commission of $500 for each car sold. How many cars would need to be sold to make the total pay the same?
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
let’s two numbers be x and y
if the sum of two numbers is 32, we have
x%2By=32....solve for x
x=32-y.....eq.1

if one number is 10 less than the other, we have
x=y-10....eq.2

from eq.1 and eq.2 we have
32-y=y-10
32%2B10=y%2By
2y=42
y=21

go to
x=y-10....eq.2, substitute y
x=21-10
x=11
The smaller number is: 11
The larger number is: 21


Ervin has been offered positions by two car dealers.
The first company pays a salary of $20000 plus a commission of $300 for each car sold.
let the number of cars sold be x
20000%2B300x

The second pays a salary of $15000 plus a commission of $500 for each car sold
15000%2B500x
How many cars would need to be sold to make the total pay the same?
20000%2B300x=15000%2B500x
20000-15000=500x-300x
5000=200x
x=5000%2F200
x=25

25 cars would need to be sold to make the total pay the same