SOLUTION: Find the equation (in terms of x) of the line through the points (-2,-4) and (2,4). Given a line passes through point (-9,2) and the origin, find the equation of the line.

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Find the equation (in terms of x) of the line through the points (-2,-4) and (2,4). Given a line passes through point (-9,2) and the origin, find the equation of the line.      Log On


   

Question 1205695: Find the equation (in terms of x) of the line through the points (-2,-4) and (2,4).
Given a line passes through point (-9,2) and the origin, find the equation of the line.
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

use given points (-2,-4) and (2,4) to find a slope
m=%284-%28-4%29%29%2F%282-%28-2%29%29=8%2F4=2
y=2x%2Bb....use one point to calculate b
4=2%2A2%2Bb
4=4%2Bb
b=4-4
b=0
your equation is
y=2x


Given a line passes through point (-9,2) and the origin, find the equation of the line.
a line passes through points
(-9,2)
(0,0)=> y-intercept b=0
m=%280-2%29%2F%280-%28-9%29%29=-2%2F9
y=-%282%2F9%29x%2B0
your equation is
y=-%282%2F9%29x