SOLUTION: Solve the following quadratic equations (if possible)*True or False* using the emojis as independent variables. Feel free to copy and paste the soccer ball to show your work. a.

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Solve the following quadratic equations (if possible)*True or False* using the emojis as independent variables. Feel free to copy and paste the soccer ball to show your work. a.      Log On


   

Question 1203120: Solve the following quadratic equations (if possible)*True or False* using the emojis as independent variables. Feel free to copy and paste the soccer ball to show your work.
a.) 12⚽ ² - 75 =0
⚽ = ?

b.) 3⚽ ² +7= -7⚽
⚽ = ?

c.) - 5(⚽+3)² +9= -71
⚽ = ?

d.) 3⚽ ² - 5⚽+ 15= - 3⚽ ² +6⚽+50
⚽ = ?

Found 3 solutions by math_tutor2020, josgarithmetic, ikleyn:
Answer by math_tutor2020(3816) About Me  (Show Source):
You can put this solution on YOUR website!

Why is your teacher insisting on you use emojis as the variable?
A simple letter would suffice.

I'll do part (a) to get you started.
12x^2 - 75 = 0
12x^2 = 75
x^2 = 75/12
x^2 = 6.25
x = plus minus sqrt(6.25)
x = sqrt(6.25) or x = -sqrt(6.25)
x = 2.5 or x = -2.5
x = 5/2 or x = -5/2


Another approach for part (a) involves the quadratic formula
a = 12, b = 0, c = -75
x+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29

x+=+%28-0%2B-sqrt%28%280%29%5E2-4%2812%29%28-75%29%29%29%2F%282%2812%29%29

x+=+%280%2B-sqrt%283600%29%29%2F%2824%29

x+=+%280%2B-++60%29%2F%2824%29

x+=+%280%2B60%29%2F%2824%29 or x+=+%280-60%29%2F%2824%29

x+=+%2860%29%2F%2824%29 or x+=+%28-60%29%2F%2824%29

x+=+5%2F2 or x+=+-5%2F2

x+=+2.5 or x+=+-2.5
The quadratic formula involves more work, compared to the first method, but it's good to get practice with alternative routes.

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
(d)

Instructions seem inconsistent. "Solve" or determine if True or False? Which? Assuming decide if T or F.

v for the variable
3d%5E2-5d%2B15=-3d%5E2%2B6d%2B50

Try take righthand side, for identical degree-two term.
3d%5E2-5d%2B15=3d%5E2-6d-50
The corresponding terms must be equal; and they are obviously not.
Degree-one terms not equal. Degree-zero, the constant terms are not equal.

The given equation is false. The equation can be solved; but that was not the question.

Answer by ikleyn(52778) About Me  (Show Source):
You can put this solution on YOUR website!
.

Looking into this assignment, my impression is


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        darkness deepens


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