Question 1199734: A basketball shot is taken from a horizontal distance of 5 m from the hoop.
The height of the ball can be modelled by
the relation h = - 7.3t² + 8.25t + 2.1,
where h is the height, in metres, and t is the time, in seconds, since the ball was released.
a) From what height was the ball released?
b) What was the maximum height reached by the ball?
c) If the ball reached the hoop in 1 s, what was the height of the hoop?
Found 2 solutions by htmentor, ikleyn:
Answer by htmentor(1343)   (Show Source):
You can put this solution on YOUR website! a) The initial height at t=0 is h(0) = 2.1
b) The maximum height occurs at the time where dh/dt = 0
dh/dt = 0 = -8.25/-14.6 = 0.565 s -> h = -7.3(0.565)^2 + 8.25(0.565) + 2.1 = 4.43 m
c) h(1) = 3.05 m
Answer by ikleyn(52780)  (Show Source):
You can put this solution on YOUR website! .
A basketball shot is taken from a horizontal distance of 5 m from the hoop.
The height of the ball can be modelled by
the relation h = - 7.3t² + 8.25t + 2.1,
where h is the height, in metres, and t is the time, in seconds, since the ball was released.
a) From what height was the ball released?
b) What was the maximum height reached by the ball?
c) If the ball reached the hoop in 1 s, what was the height of the hoop?
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The formula for the height in the post is incorrect.
Therefore, the entire problem is DEFECTIVE and NONSENSICAL.
As the problem is worded, printed and presented, it makes it
totally clear that the problem composer DOES NOT KNOW the subject.
The problem is FATALLY WRONG.
My friendly advise to you is to throw it to the closest garbage bin as soon as you can.
The source of this problem is COMPROMISED forever.
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This problem is posed incorrectly and teaches to wrong conceptions.
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To learn right conceptions and basic knowledge, read the lesson
- Introductory lesson on a projectile thrown-shot-launched vertically up
in this forum.
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