Question 1197633: 15. There are two consecutive even integers. The square of the larger one is three hundred eight more than the smaller one. Which of the following equations could you use to find the smaller integer?
A. (x + 2)^2 - 308 = x
B. (x + 2)^2 + 308 = x
C. (x + 1)^2 + 308 = x
D. (x + 1)^2 = x - 308
E. (x + 1)^2 - 308 = x
F. (x + 2)^2= x - 308
Found 4 solutions by greenestamps, math_tutor2020, josgarithmetic, ikleyn:
Answer by greenestamps(13198)   (Show Source):
You can put this solution on YOUR website!
If the smaller of two consecutive even integers is x, then the larger one is x+2.
The given information tells us that you can find the smaller one by subtracting 308 from the square of the larger. That is what option A says.
ANSWER: A
Answer by math_tutor2020(3816)  (Show Source):
You can put this solution on YOUR website!
Consecutive even integers are things like 2,4,6 or 28,30,32
The integers are spaced 2 apart and are even. I.e. they are even numbers that follow one after another.
x = smaller even number
x+2 = even number just after x, aka the larger of the two values
(larger)^2 = (smaller) + 308
(larger)^2 - 308 = smaller
(x+2)^2 - 308 = x
which points us to choice A as the answer.
Answer by josgarithmetic(39617) (Show Source):
You can put this solution on YOUR website! Exactly as described,
x, the smaller integer
x+2, the larger integer
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The square of the larger one is three hundred eight more than the smaller one.
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Fairly simple algebra to solve for x.
Answer by ikleyn(52778)  (Show Source):
You can put this solution on YOUR website! .
For clarity, equation written in the post by @josgarithmetic is INCORRECT :  .
This incorrect equation may lead you to wrong inferences.
Therefore, for the sake of security of your mind, simply ignore the post by @josgarithmetic.
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