SOLUTION: sum=2/3, product= 5/3

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: sum=2/3, product= 5/3       Log On


   



Question 1196265: sum=2/3, product= 5/3

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
sum=2/3, product= 5/3
You should specify how many terms:
a + b = 2/3, a*b = 5/3
-----------
a + b + c = 2/3, a*b*c = 5/3
etc
============
If it's 2 terms:
a + b = 2/3, a*b = 5/3
b = -a + 2/3
a*(-a + 2/3) = 5/3
-3a^2 + 2a = 5
3a^2 - 2a + 5 = 0
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 3x%5E2%2B-2x%2B5+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%28-2%29%5E2-4%2A3%2A5=-56.

The discriminant -56 is less than zero. That means that there are no solutions among real numbers.

If you are a student of advanced school algebra and are aware about imaginary numbers, read on.


In the field of imaginary numbers, the square root of -56 is + or - sqrt%28+56%29+=+7.48331477354788.

The solution is , or
Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+3%2Ax%5E2%2B-2%2Ax%2B5+%29