Question 1195914: find two consecutive positive integers such that the square of the second integer added to four times the first is equal to 41 Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! find two consecutive positive integers such that the square of the second integer added to four times the first is equal to 41
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n^2 + 4(n-1) = 41
n^2 + 4n - 45 = 0
(n-5)*(n+9) = 0
n = 5