SOLUTION: find two consecutive positive integers such that the square of the second integer added to four times the first is equal to 41

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Question 1195914: find two consecutive positive integers such that the square of the second integer added to four times the first is equal to 41
Answer by Alan3354(69443) About Me  (Show Source):
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find two consecutive positive integers such that the square of the second integer added to four times the first is equal to 41
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n^2 + 4(n-1) = 41
n^2 + 4n - 45 = 0
(n-5)*(n+9) = 0
n = 5