SOLUTION: A plane traveled from Moncton to Winnipeg, a distance of 1940km. On the return
trip, the plane’s speed increased by 100km/h due to a tailwind. The total round trip took
6 hour
Question 1195809: A plane traveled from Moncton to Winnipeg, a distance of 1940km. On the return
trip, the plane’s speed increased by 100km/h due to a tailwind. The total round trip took
6 hours. Find the average speed of the plane in both parts of its journey. Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! A plane traveled from Moncton to Winnipeg, a distance of 1940km. On the return
trip, the plane’s speed increased by 100km/h due to a tailwind. The total round trip took
6 hours. Find the average speed of the plane in both parts of its journey.
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v = plane's groundspeed with no wind.
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Avg speed of the round-trip = 2*v*(v+100)/(v + v+100) = (2v^2 + 200v)/(2v+100)
Avg speed = 1940*2/6 = 1940/3 km/hr
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(2v^2 + 200v)/(2v+100) = 1940/3
(6v^2 + 600v)/(2v+100) = 1940
6v^2 + 600v = 1940*(2v+100)
3v^2 + 300v = 970*(2v+100) = 1940v + 97000
3v^2 - 1640v - 97000 = 0