SOLUTION: A parking lot contains motorcycles (2 wheels) and cars (4 wheels). There are 35 vehicles and 114 wheels. How many motorcycles and cars are there? how to solve using elimin

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Question 1195779: A parking lot contains motorcycles (2 wheels) and cars (4 wheels).
There are 35 vehicles and 114 wheels. How many motorcycles and cars are
there? how to solve using elimination method
Found 2 solutions by MathLover1, Alan3354:
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

let motorcycles (2 wheels) be x and cars (4 wheels) y
if there are 35 vehicles we have
x%2By=35...........eq.1
if there 114 wheels, we have
2x%2B4y=114...........eq.2
solve the system
x%2By=35...........eq.1
2x%2B4y=114...........eq.2
-------------------------------------------ultiply eq1 by 4
4x%2B4y=140...........eq.1
2x%2B4y=114...........eq.2
-------------------------------------------- subtrat eq2 fro eq1 to eliinate y
4x%2B4y-%282x%2B4y%29=140-114
4x%2B4y-2x-4y=26
+2x=26
+x=13
go to
x%2By=35...........eq.1 substitute x
13%2By=35
y=35-13
y=22

there are 13 motorcycles and +22 cars

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
A parking lot contains motorcycles (2 wheels) and cars (4 wheels).
There are 35 vehicles and 114 wheels. How many motorcycles and cars are
there? how to solve using elimination method
---------------
2M + 4C = 114 ---- # of wheels
M + C = 35
---------------
2M + 4C = 114 --- divide by 2
M + 2C = 57
M + C = 35
-------------------- Subtract
C = 22
etc.