Question 118946: A quadratic equation is given by y=2x^2 - 6bx+3.What is the value of 'b' if the equation of the axis of symmetry is x=9 ? I think the answer is 6 but I really don't fully understand, can someone please explain this to me ?
Found 5 solutions by jim_thompson5910, stanbon, Earlsdon, josmiceli, scott8148: Answer by jim_thompson5910(35256) (Show Source): Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A quadratic equation is given by y=2x^2 - 6bx+3.What is the value of 'b' if the equation of the axis of symmetry is x=9 ? I think the answer is 6 but I really don't fully understand, can someone please explain this to me ?
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In the general form of a quadratic. y = ax^2+bx+c,
the axis of symmetry is x = -b/2a Where "b" is the coefficient of the 2nd term.
In Your Problem, "b" = -6b
So -(-6b)/(2*2) = 9
3b/2 = 9
b = 6
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Cheers,
Stan H.
Answer by Earlsdon(6294) (Show Source): Answer by josmiceli(19441) (Show Source): Answer by scott8148(6628) (Show Source):
You can put this solution on YOUR website! for a quadratic of the form ax^2+bx+c, the equation for the axis of symmetry is x=-b/2a
in this case 9=-(-6b)/(2*2) __ 36=6b __ 6=b
looking at the quadratic formula can help to clarify
___ the formula gives two solutions and
the average of the two solutions (which is the midline of the graph) is -b/2a
__ the square root portions cancel each other
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