SOLUTION: Find the quadratic function with integral coefficients having the given zeros of -2 and 7/2

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Question 1188807: Find the quadratic function with integral coefficients having the given zeros of -2 and 7/2
Found 2 solutions by MathLover1, ikleyn:
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

given:
zeros of -2 and 7%2F2

f%28x%29=%28x-x%5B1%5D%29%28x-x%5B2%5D%29
f%28x%29=%28x-%28-2%29%29%28x-7%2F2%29
f%28x%29=%28x%2B2%29%28x-7%2F2%29
f%28x%29=x%5E2+-+%283%2F2%29x+-+7
+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+x%5E2+-+%283%2F2%29x+-+7%29+

Answer by ikleyn(52780) About Me  (Show Source):
You can put this solution on YOUR website!
.
Find the quadratic function with integral coefficients having the given zeros of -2 and 7/2
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The answer f%28x%29=x%5E2+-+%283%2F2%29x+-+7 in the post by @MathLover1 is INCORRECT,

since her polynomial is not with integer coefficients.


To get a correct answer, you should multiply that polynomial by 2 to rid of the denominator.


So, a correct answer is  f(x) = 2x^2 -3x - 14.


You may use any integer multiple of the last polynomial, too,  for example


    4x^2 - 6x - 28,

or

    6x^2 - 9x - 42.


They define DIFFERENT QUADRATIC FUNCTIONS, but they all HAVE THE ASSIGNED ZEROES.


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By the way,  the question in your post is posed  INCORRECTLY.

It asks about  " the function ",  but in reality,  there are  MANY  such functions;
actually,  even  INFINITELY  MANY.

So the correct question should be  " find A quadratic function . . . "