Question 1188452: Find the equation of the quadratic given its real roots 2-√3 and 2+√3 which passes through the point (1, -2). Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! the factors are x-2+sqrt(3) and x-2- sqrt(3)
the basic form of the quadratic is x^2-4x+1, multiplying those factors together (there are 9 terms)
y=a(x^2-4x+1) is the general form
-2=a(-2)
a=1
a=(2/11)
the equation is y=x^2-4x+1