SOLUTION: Make a rectangle with an area which is at most 35cm, where the width is 2cm more than its length Find the possible dimensions of the rectangle. (with solution)

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Make a rectangle with an area which is at most 35cm, where the width is 2cm more than its length Find the possible dimensions of the rectangle. (with solution)      Log On


   

Question 1185815: Make a rectangle with an area which is at most 35cm, where the width is 2cm more than its length Find the possible dimensions of the rectangle. (with solution)
Found 2 solutions by josgarithmetic, greenestamps:
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
x, the length
x+2, the width
0%3Cx%28x%2B2%29%3C=35

Basic Fact: 5 x 7 = 35

0%3C5%2A7%3C=35, but 5 cm by 7 cm is not the only possibility.

Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


x = length
x+2 = width

The area (length times width) is at most 35 cm^2 (not 35 cm):

x%28x%2B2%29%3C=35
x%5E2%2B2x%3C=35
x%5E2%2B2x-35%3C=0
%28x%2B7%29%28x-5%29%3C=+0

-7%3C=x%3C=5

Obviously negative values make no sense in the problem. So

ANSWER: The length x is less than 5 (and not negative)