SOLUTION: Please help me solve this problem. I have no idea how to arrange word problems .
The length of a rectangle is 3 cm more than 2 times its width. If the area of the rectangle is
Question 118400: Please help me solve this problem. I have no idea how to arrange word problems .
The length of a rectangle is 3 cm more than 2 times its width. If the area of the rectangle is 93 cm2, find the dimensions of the rectangle to the nearest thousandth. Place your answers in the blanks provided.
Width = __________cm, Length = _________cm.
You can put this solution on YOUR website! The length of a rectangle is 3 cm more than 2 times its width. If the area of the rectangle is 93 cm2, find the dimensions of the rectangle to the nearest thousandth.
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Let the width be x cm ;Then the length is 2x+3 cm
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Area = width*length
93 = x(2x+3)
93 = 2x^2+3x
2x^2+3x-93 = 0
x = [-3 +- sqrt(9 -4*2*-93)]/4
x = [-3 + sqrt(753)]/4
x = [-3 + 27.44]/4
x = 24.44/4
x = 6.11 cm (width)
2x+3 = 15.22 cm (length)
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Cheers,
Stan H.
You can put this solution on YOUR website!
given:
The length of a rectangle is more than times its width .
then
If the area of the rectangle is
to find: the dimensions of the rectangle to the nearest thousandth.
since the area is , we will have:
..
find only positive root ( the width cannot be negative)
(