Question 118393: What is the equation of the line passing through the point (6,-3) and perpendicular to the line containing the points (2,-4) and (-5,1) ? Answer by tutorcecilia(2152) (Show Source):
You can put this solution on YOUR website! What is the equation of the line passing through the point (6,-3) and perpendicular to the line containing the points (2,-4) and (-5,1) ?
Find the slope of the first line:
Slope #1: m=
m=
.
Slope #2 is perpendicular to Slope #1: m= [the negative reciprocal of slope #1]
.
Using the points (6, -3) and the slope of Line #2, plug-in to the slope-intercept formula of y=mx+b
.
y=mx+b
-3=(7/5)(6)+b [solve for the b-value]
-3=42/5+b
-3-42/5=b
-15/5-42/5=b
-57/5=b
.
Plug-in the slope and b-value of Line #2:
y=mx+b
y=
