Question 1180466: A rectangular chicken yard was built against an existing
shed wall. 30 m of fencing was used to enclose 108 m2.
Find the dimensions of the yard.
Found 2 solutions by ikleyn, MathLover1:
Answer by ikleyn(52781)   (Show Source):
You can put this solution on YOUR website! .
A rectangular chicken yard was built against an existing
shed wall. 30 m of fencing was used to enclose 108 m2.
Find the dimensions of the yard.
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Let x be the width perpendicular to the wall, in meters.
Then the length parallel to the wall is (30 - 2x) meters.
The area is x*(30-2x), and it is 108 m^2, according to the condition.
So,
x*(30-2x) = 108
is your area equation to find x.
Simplify
30x - 2x^2 = 108
2x^2 - 30x + 108 = 0
x^2 - 15x + 54 = 0
(x-6)*(x-9) = 0
There are two roots, 6 and 9, and they BOTH are meaningful.
ANSWER. There are two solutions.
One solution is (the width = 6 m perpendicular to the wall, the length is 30-2*6 = 18 m parallel to the wall).
The other solution is (the width = 9 m perpendicular to the wall, the length is 30-2*9 = 12 m parallel to the wall).
Solved.
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Regarding the post by @MathLover1, she made an arithmetic error on the way, so her solution is FATALLY WRONG.
For your safety, ignore her post.
Answer by MathLover1(20849)  (Show Source):
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