SOLUTION: the height of a ball thrown upward after a given amount of time is h = - 4.9t ^ 2 + 29.4t + 1 where h represents the height of the ball in metres , and t represents the time elapse
Question 1178877: the height of a ball thrown upward after a given amount of time is h = - 4.9t ^ 2 + 29.4t + 1 where h represents the height of the ball in metres , and t represents the time elapsed since the ball has been thrown . Determine the maximum height of the ball and at what time this occurs a) What is the maximum height reached by the ball? b ) How long is the ball above a height of 40 m ? c) When does the ball hit the ground ? Found 2 solutions by Solver92311, ikleyn:Answer by Solver92311(821) (Show Source):
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