SOLUTION: sketch the graph of the following functions f(x)=-2*(3)^x and g(x)=4*(1/3)^x

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: sketch the graph of the following functions f(x)=-2*(3)^x and g(x)=4*(1/3)^x      Log On


   



Question 117748: sketch the graph of the following functions
f(x)=-2*(3)^x and g(x)=4*(1/3)^x

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
I'll do the first one to show you how to do these

f%28x%29=-2%2A3%5Ex Start with the given expression
In order to plot an exponential function, we need to plot some points
We can start at any x value, so lets start at x=0

f%280%29=-2%2A3%5E0 Plug in x=0

f%280%29=-2%2A1 Raise 3 to the zeroth power to get 1

f%280%29=-2 Multiply -2 by 1 to get -2

So when x=0, y=-2. So our first point is (0,-2)


----Now lets find another point----
f%281%29=-2%2A3%5E1 Plug in x=1

f%281%29=-2%2A3 Raise 3 to the first power to get 3

f%281%29=-6 Multiply -2 by 3 to get 6

So when x=1, y=-6. So our second point is (1,-6)


----Now lets find another point----
f%282%29=-2%2A3%5E2 Plug in x=-2

f%282%29=-2%2A9 Raise 3 to the second power to get 9

f%282%29=-18 Multiply -2 by 9 to get -18

So when x=2, y=-18. So our third point is (2,-18)


----Now lets find another point----
f%283%29=-2%2A3%5E3 Plug in x=3

f%283%29=-2%2A27 Raise 3 to the third power to get 27

f%283%29=-54 Multiply -2 by 27 to get -54

So when x=3, y=-54. So our fourth point is (3,-54)



===============================================================================

Now lets make a table of the values we have calculated
xy
0-2
1-6
2-18
3-54
Now plot the points



Connect the points to form the graph y=-2%2A3%5Ex
Graph of y=-2%2A3%5Ex through the points solved for earlier