SOLUTION: Determine the signs of the roots of the equation (if they exist) without solving the equation: {{{x^2-2x-1=0}}} Found the discriminant (8) But apparently the answer isn't 2 p

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Question 1177234: Determine the signs of the roots of the equation (if they exist) without solving the equation:
x%5E2-2x-1=0
Found the discriminant (8)
But apparently the answer isn't 2 positive roots, so I'm stuck

Found 3 solutions by ankor@dixie-net.com, MathLover1, ikleyn:
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Determine the signs of the roots of the equation (if they exist) without solving the equation:
x%5E2-2x-1=0
The discriminant
-2%5E2+-+4%2A1%2A-1
4 + 4 = 8
Positive means two distinct real roots, not necessarily both positive

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
using the Descartes' Rule of Signs
x%5E2+-2x+-1....look for changes in sine
So, the coefficients are 1,-2,-1.
As can be seen, there is 1 change.
This means that there is 1 positive real root.

Replace x by %28-x%29:
%28-x%29%5E2+-+2%28-x%29+-1=x%5E2+%2B+2x+-1
The coefficients are 1,2,-1.
As can be seen, there is 1 change.
This means that there is 1+negative real root.

The discriminant determines the nature of the roots of a quadratic equation. The word 'nature' refers to the types of numbers the roots can be — namely real, rational, irrational or imaginary.
If the discriminant is positive, we know that we have 2 real solutions that could be both positive, both negative, or one solution is positive and other is negative

so, b%5E2-4ac=%28-2%29%5E2-4%2A1%28-1%29=8=>discriminant is positive, we know that we have 2 real solutions


Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.

The discriminant of the equation   d = b^2 - 4ac = (-2)^2 + 4*1*(-1) = 4 + 4 = 8   is a positive real number,

so the roots are real numbers.


Next,  according to the  Vieta's theorem,  the product of the roots is equal to the constant term,  which is  -1  in this case,

so the roots are of opposite signs:  one root is a positive real number,  while another root is a negative real number.


That's all.


Solved,  answered,  explained and completed.