SOLUTION: Find the quadratic function y​=f(x) whose graph has a vertex ​(-2​,​4) and passes through the point ​(-6​,0). Write the function in standard form.

Hi



Using the vertex form of a parabola,  where(h,k) is the vertex

Vertex (-2,4) 

 y = a(x+2)^2 + 4 

P​(-6​,0)

0 = 16a+ 4

-4/16 = a  = -.25



, the vertex form of a parabola



As to Standard form (If necessary):

 y =-.25(x^2 + 4x + 4) + 1 =-.25x^2 - x - 1 + 4 = -.25x^2 - x + 3