SOLUTION: How do you solve 2n^2-4n=6 and then put it into a table or graph?

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Question 117535: How do you solve 2n^2-4n=6 and then put it into a table or graph?
Found 2 solutions by checkley71, stanbon:
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
THE ANSWER TO YOUR QUESTON ON SQUARE ROOT SIGN IS NO!
I USE (SQRT).
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2n^2-4n-6=0
to graph this equation we set it =y. thus:
y=2x^2-4x-6
+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+y+=+2x%5E2-4x+-6%29+ (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, y = 2x^2 -4x -6).

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
How do you solve 2n^2-4n=6 and then put it into a table or graph?
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2n^2-4n-6 = 0
2(n^2-2n-3) = 0
(n-3)(n+1) = 0
n = 3 or n = -1
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y= 2n^2-4n-6
It has x-intercepts at (3,0) and at (-1,0)
The vertex is at x=-b/2a = 4/(4) = 1 ; f(1) = 2-4-6 = -8
So the vertex is at (1,-8)
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With those three points you can graph the parabola.
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Graph:
graph%28400%2C300%2C-10%2C10%2C-10%2C10%2C2x%5E2-4x-6%29
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Cheers,
Stan H.