SOLUTION: I am having some troubles with solving for the variable in equation {{{2(y-1)^2=4(y+1)^2}}} What I have so far is...... 2(y-1)(y-)=4(y+1)(y+1) 2(y^2-y-y-1)=4(y^2+y+y+1) 2y^2-

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: I am having some troubles with solving for the variable in equation {{{2(y-1)^2=4(y+1)^2}}} What I have so far is...... 2(y-1)(y-)=4(y+1)(y+1) 2(y^2-y-y-1)=4(y^2+y+y+1) 2y^2-      Log On