SOLUTION: The weight of an object varies inversely as the square of the​ object's distance from the center of Earth. The radius of Earth is 3960 miles. a. If an astronaut weighs 130 po

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: The weight of an object varies inversely as the square of the​ object's distance from the center of Earth. The radius of Earth is 3960 miles. a. If an astronaut weighs 130 po      Log On


   



Question 1173967: The weight of an object varies inversely as the square of the​ object's distance from the center of Earth. The radius of Earth is 3960 miles.
a. If an astronaut weighs 130 pounds on the surface of​ Earth, how much does she weigh 6,000 miles above the surface of​ Earth?
b. If a miner weighs 218 pounds on the surface of​ Earth, how much does he weigh 12 miles below the surface of​ Earth?

Answer by ikleyn(52778) About Me  (Show Source):
You can put this solution on YOUR website!
.

            For your info,  and for the info of the person who created/composed this problem.


For an object located deeply inside the Earth globe,  this statement is  INVALID,
that the weight of such an object is inversely proportional to the square of the distance from the  Earth center.

In this case,  outer layers of the  Earthen globe produce  ZERO  net gravitational force,
and only interior mass of the  Earthen globe participates to make the net gravity force.


As a result,  the inverse proportionality law  DOES  NOT  work for the bodies inside the  Earthen globe.


For example and as a consequence of this fact,  the weight of the body located  AT  THE  CENTER
of the  Earthen globe is equal to  ZERO,  but not an infinity . . .


It was discovered by sir  Isaak  Newton more than  330 years ago,  and is well known fact since then for all who knows the subject.


THEREFORE,  the part  (b)  of your problem can only confuse a professional reader,
and makes it clear that the person who created this problem is unfamiliar with elementary Physics,
so you better take it off . . .


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