SOLUTION: A positive integer squared plus 6 times its consecutive integer is equal to 22. Find the integers

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Question 1171166: A positive integer squared plus 6 times its consecutive integer is equal to 22. Find the integers
Found 2 solutions by ikleyn, MathLover1:
Answer by ikleyn(52776) About Me  (Show Source):
You can put this solution on YOUR website!
.

    n^2 + 6(n+1) = 22.


Solve this quadratic equation.

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Happy solving (!)


Keep me informed about your progress.


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The answer  " -8 and -7 "  from  @MathLover1 is  INCORRECT  (!)



Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

let consecutive integers be x and x%2B1
A positive integer squared: x%5E2
plus
6 times its consecutive integer: 6%28x%2B1%29
is equal to 22
put all together:
x%5E2%2B6%28x%2B1%29=22....solve for x
x%5E2%2B6x%2B6-22=0
x%5E2%2B6x-16=0....factor
%28x+-+2%29+%28x+%2B+8%29+=+0

solutions:
x=2
or
x=-8

consecutive integers are 2 and 3
or
consecutive integers be -8 and -7