SOLUTION: Some students at L.C.V.I. held a bake sale
recently to raise money for a field trip.
They charged $7 for fruit pies and $10 for
meat pies. They sold a total of 52 pies and
earn
Question 1170779: Some students at L.C.V.I. held a bake sale
recently to raise money for a field trip.
They charged $7 for fruit pies and $10 for
meat pies. They sold a total of 52 pies and
earned $424. How many of each type of
pie did they sell? Answer by greenestamps(13198) (Show Source):
The total sales, at $7 for each fruit pie and $10 for each meat pie, was $424:
(1)
The total number of pies was 52:
(2)
One possible way to solve this pair of equation is to multiply the second equation by 10 and compare the resulting equation to (1):
(the difference between those two equations)
ANSWER: the number of fruit pies sold was 32; the number of meat pies was 52-32=20.
You can solve the problem informally, using EXACTLY the same calculations, like this:
(1) If all 52 pies were meat pies, the total sales would be $520.
(2) The actual total sales was $424, which is $96 less than $520.
(3) Each fruit pie costs $3 less than each meat pie.
(4) The number of fruit pies sold, to bring the sales total down $96, from $520 to $424, is $96/$3 = 32.
