SOLUTION: A rectangle has perimeter 56 feet and it’s area is 180 sq feet find the dimensions of this rectangle. Length = Width = Thank you

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Question 1169125: A rectangle has perimeter 56 feet and it’s area is 180 sq feet find the dimensions of this rectangle.
Length =
Width =
Thank you
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

Length =L
Width =W
perimeter=>P=2%28L%2BW%29
area=> A=LW
A rectangle has perimeter 56 feet we have
56ft=2%28L%2BW%29...solve for L
56ft%2F2=L%2BW
28ft-W=L....eq.1

and it’s area is 180 sq feet find the dimensions of this rectangle, we have
180=LW..solve for L
180%2FW=L...........eq.2
from eq.1 and eq.2 we have
28ft-W=180%2FW....solve for W
28W-W%5E2=180
0=W%5E2-28W%2B180....factor
0=W%5E2-10W-18W%2B180
0=%28W%5E2-10W%29-%2818W-180%29
0=W%28W-10%29-18%28W-10%29%7D%7D%0D%0A%7B%7B%7B0+=+%28W+-+18%29+%28W+-+10%29
=>W=10ft or W=18ft
28ft-W=L....eq.1, substitute W=10ft
28ft-10ft=L
L=18ft
Length =18ft
Width =10ft