SOLUTION: Explain how you know when using the quadratic formula that a quadratic relation has zero, one or two x-intercepts.

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Question 1168581: Explain how you know when using the quadratic formula that a quadratic relation has zero, one or two x-intercepts.

Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!

+ax%5E2+%2B+bx+%2B+c+=+0+
The quadratic formula of course is:
+x+=+%281%2F%282a%29%29%28-b+%2B-+sqrt%28b%5E2-4ac%29%29+

D = +b%5E2-4ac+ is the discriminant, and there are three possibilities:
D < 0 ===> no real roots (no x-axis crossing)
D = 0 ===> real root with multiplicity 2 (one x-axis crossing)
D > 0 ===> two distinct real roots (two x-axis crossings)


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Side-note/if you are curious...
The quadratic formula can be derived from ax%5E2+%2B+bx+%2B+c+=+0+ by completing the square:
+ax%5E2+%2B+bx+%2B+c+=+0+
Divide thru by a, then subtract c/a from both sides:
+x%5E2+%2B+%28b%2Fa%29x+=+-c%2Fa+
Complete the square by adding +%28b%2F%282a%29%29%5E2+ to both sides:
+x%5E2+%2B+%28b%2Fa%29x+%2B+%28b%2F%282a%29%29%5E2+=+-c%2Fa+%2B+%28b%2F%282a%29%29%5E2+
Factor LHS:
+%28x+%2B+b%2F%282a%29%29+%5E2++=+-c%2Fa+%2B+%28b%2F%282a%29%29%5E2+

Take square root of both sides (introduces +/- on RHS):
+++x+%2B+b%2F%282a%29+ = +/- +sqrt%28b%5E2%2F%284a%5E2%29+-+c%2Fa%29+

Subtract b%2F%282a%29 from both sides:
++x+=+-b%2F%282a%29+%2B-++sqrt%28b%5E2%2F%284a%5E2%29+-+c%2Fa%29+
Tidy up:

++x+=+-b%2F%282a%29+%2B-+sqrt%28%28b%5E2+-+4ac%29%2F%284a%5E2%29%29+

++x+=+%28-b+%2B-+sqrt%28b%5E2+-+4ac%29%29+%2F+%282a%29+